1-1.1x+0.3x^2=0

Solution for 1-1.1x+0.3x^2=0 equation:

1-1.1x+0.3x^2=0

a = 0.3; b = -1.1; c = +1;
Δ = b2-4ac
Δ = -1.12-4·0.3·1
Δ = 0.01
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.1)-\sqrt{0.01}}{2*0.3}=\frac{1.1-\sqrt{0.01}}{0.6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.1)+\sqrt{0.01}}{2*0.3}=\frac{1.1+\sqrt{0.01}}{0.6}
$